[Level1] 성격 유형 검사하기 (C++)

#include <string>
#include <vector>
#include <map>
using namespace std;

string FindType(map<char,int>& table) {
    string answer = "";
    
    if(table['R'] >= table['T']) answer += "R";
    else answer += "T";

    if(table['C'] >= table['F']) answer += "C";
    else answer += "F";

    if(table['J'] >= table['M']) answer += "J";
    else answer += "M";

    if(table['A'] >= table['N']) answer += "A";
    else answer += "N";
    
    return answer;
}

string solution(vector<string> survey, vector<int> choices) {
    map<char, int> table;
    
    for(int idx = 0; idx < choices.size(); idx++) {
        if(choices.at(idx) < 4) {
            table[survey[idx][0]] = table[survey[idx][0]] + (4 - choices[idx]);
        } else if (choices.at(idx) > 4){
            table[survey[idx][1]] = table[survey[idx][1]] + (choices[idx] - 4);
        }
    }
    
    string answer = FindType(table);
    return answer;
}